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    Margaret's health
    by onetenor πŸ‡¬πŸ‡§ ( Sub-Lieutenant)
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    onetenor
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    Doug they don't say what Mah is for. just the figure alongside the voltage. A 1000 and a100 Ohm both too big so will try 10 to 20 range. thanks Doug πŸ‘πŸ‘ I can't do pics. Not equipped.
    onetenor
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    Yes 7, The Grove, Meliden. Prestatyn. LL19 8LBπŸ‘ Have one (or whatever)πŸ€“ for me in the Pic
    RNinMunich
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    Hi John, that's 0.5A (or 500mA) not 5A!
    Do you mean 400mAH (which is battery capacity) or 400mA current?
    If 400mA charge current then use the 15Ohm resistor.
    If the battery capacity was 400mAh then using the C/10 rule, i.e. 40mA charge current you would need a 150Ohm resistor. And charge for about 12 hours.
    For a 250mAh battery probably a 180 or 220Ohm resistor.
    Any chance of a photo showing any and all markings on the 'Wart'?
    Off to 'Bedfordshire now, I'll do some proper calcs tomorrow.
    All the best, Doug 😎
    Young at heart - slightly older in other places πŸ˜‰ Cheers Doug
    NPJ
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    I live in Caerwys off A55 Junction 31.

    I think you are Prestatyn or close by.

    Is that right?

    Regards.

    NPJ
    NPJ
    onetenor
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    Thanks Doug but can't see a current rating. Just volts in and out. I thought about 10 Ohms but your numbers are right . is 5 amps a bit high. it's only for up to 4 Nimh AA cells after all or are you playing safe? Sorry I don't know how I missed previous answers. A similar one shows 400 Mah. |But thinking back I think the original was 7.2 v @w250 Mah. I only think though.
    onetenor
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    Thanks NPJ No need at present but if you want to drop by feel welcome. Where is nearby?πŸ‘
    NPJ
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    Thoughts are with you Onetenor.

    If I can help I live quite close.

    NPJ.
    NPJ
    RNinMunich
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    Hi John, Yes, two or three times actually.
    I wanted to know the current the charger is rated for.
    Should be on a label or embossed on the case somewhere.
    Given that the calculation is easy.
    V=I*R --> R=V/I
    Given an initial charging voltage of approx 7.4 +10% = 8.14V and a charge current of 0.5A; V=15-8.14 --> 6.86
    R=6.86/0.5 --> 13.72Ω so you need a 12 or 15Ω resistor.
    P=I*V = 0.5*6.86 --> 3.43W.
    So you need at least a 5W resistor.
    A ceramic resistor if there is enough space.
    Alles klar Herr Kommissar? πŸ˜‰
    Cheers, Doug 😎
    Young at heart - slightly older in other places πŸ˜‰ Cheers Doug
    onetenor
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    Thanks luv you all. Btw doug did you ever reply to my query re voltage dropping. 15 v raw down to whatever needed for charging 7.4v (7.5/6 )???πŸ‘ What resistor would I need?
    RNinMunich
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    I'll second that ColinπŸ‘

    Thanks for sharing that John, warms the Cockles😊
    Congrats to Mum (and Dad!)
    All the best, Doug
    Young at heart - slightly older in other places πŸ˜‰ Cheers Doug
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